Find parametric equations for the line through (-3,-2,1) and (-1,-3,-1). The parametric equation with direction vector the displacement vector from the first point to the second, and that passes through (-3,-2,1) when t=o is x=-3+2t. y=? z=?
Added by Cynthia H.
Step 1
To do this, we subtract the coordinates of the first point from the coordinates of the second point: Direction vector = (-1 - (-3), -3 - (-2), -1 - 1) = (2, -1, -2) Now, we can write the parametric equations for the line using the given point (-3, -2, 1) and the Show more…
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