Find a polynomial function of degree 3 with real coefficients that has the given zeros. -1, 2, -4 The polynomial function is f(x) = x^3 + x^2 - 6x - 8.
Added by Shawn I.
Close
Step 1
First, we know that a polynomial function of degree 3 with real coefficients and zeros at -1, 2, and -4 can be written in the form: f(x) = a(x + 1)(x - 2)(x + 4) We can expand this to get: f(x) = a(x^3 + 3x^2 - 10x - 8) We want the coefficient of x^3 to be 1, Show more…
Show all steps
Your feedback will help us improve your experience
Tim Thornhill and 91 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find a polynomial function $f(x)$ of degree 3 with only real coefficients that satisfies the given conditions. Zeros of $-2,-1,$ and $4 ; \quad f(2)=48$
Polynomial and Rational Functions
Zeros of Polynomial Functions (II)
Find a polynomial function of degree 3 with real coefficients that has the given zeros -1,2,-5
Piyush Kumar G.
Find a polynomial function $f(x)$ of degree 3 with real coefficients that satisfies the given conditions. Zeros of $1,-1,$ and $0 ; f(2)=3$
Zeros of Polynomial Functions
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD