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'Find the angular extension of the first-order spectrum of white light from 390 nm-78Onm incident vertically onto a diffraction grating containing 17000lines inch where Tinch = 2.54cm'

          'Find the angular extension of the first-order spectrum of white light from 390 nm-78Onm incident vertically onto a diffraction grating containing 17000lines inch where Tinch = 2.54cm'
        

Added by Lisa G.

University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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'Find the angular extension of the first-order spectrum of white light from 390 nm-78Onm incident vertically onto a diffraction grating containing 17000lines inch where Tinch = 2.54cm'
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Transcript

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00:01 All right, so let's say we have a diffraction grading with about 669 ,291.
00:08 We'll say like 3 ,4 lines per meter.
00:14 And we want to find the angular extension of the forced order spectrum of white light.
00:18 So our wavelength is going to be in the range of 390 nanometers to 780 nanometers, something like this.
00:32 So what we'll have is 1 over n times the sign of theta, we'll call 1.
00:39 So it should be equal to, you know, lambda, basically, or lambda 1.
00:45 It's our smallest wavelength.
00:47 So if we find theta 1, what that's going to be is 390 times 10 to the negative, sorry, 390 times 10 to the negative 9th times 669299.
00:58 1 and we take the inverse sign of that.
01:01 Theta 1 should be about 15 .13 degrees...
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