00:01
All right, so let's say we have a diffraction grading with about 669 ,291.
00:08
We'll say like 3 ,4 lines per meter.
00:14
And we want to find the angular extension of the forced order spectrum of white light.
00:18
So our wavelength is going to be in the range of 390 nanometers to 780 nanometers, something like this.
00:32
So what we'll have is 1 over n times the sign of theta, we'll call 1.
00:39
So it should be equal to, you know, lambda, basically, or lambda 1.
00:45
It's our smallest wavelength.
00:47
So if we find theta 1, what that's going to be is 390 times 10 to the negative, sorry, 390 times 10 to the negative 9th times 669299.
00:58
1 and we take the inverse sign of that.
01:01
Theta 1 should be about 15 .13 degrees...