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Justin X.
Calculus 1 / AB
5 months, 4 weeks ago
I have a question and decided to find the area between the two curves. Y cuarto X. Raised to the power six. And why quarto minus E. Raised to the power minus three X. Over the interval? 0 to 1. Okay. Okay. So we have been given two curves and if you draw the rough sketch of the curve, this is X. This is why his first day is a wide call to X raised to the power six which is which is in even curb that is it will be symmetrical about the Y axis. Yeah. My call to express to the power six of this. Now, what I could do minus areas to the power minus three X. So why call to minus he has the power of -3x. It should look like this. Okay, okay, but when we have X equal to zero then why is minus of one? So this is minus one. It is like this. This is why I called too minus. It is to the power minus three X. Okay, now, but we have to do is I have to find the area between two curves between 0 to 1. When X equal to zero and X equals two one. Let us say X equal to win the area between the curve. So I have to take element that is small strip like this. And so the idea would be equal to Why coordinate of this? Exodus to the power six minus minus. It is to the power minus three X D X. From 0 to 1. Access to the power six plus it is to the power minus three X 0-1. Now integrating access to the power seven x 7 Plus areas. To the power of -3 x divided by -3. Because I'm into getting it. Yeah. Okay. from 0 to 1 so let us plug in let's start plugging in the limits. That would be a problem. It first one by seven bless It is to the bottom -3 x -3 And then zero. So this will be zero And this will be -1 by three. Okay so one x 7 minus one x 3 years. About three Plus one x 3. Okay so one by seven plus one by three I would be doing like this three plus seven three times 7 times -1 x three. It is about three squad units. So they should be the answer thank you.
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