00:01
There is a standard normal distribution given in this question.
00:03
Why? because there's a z value here.
00:06
Z is for standard normal distribution.
00:08
So it says we have to find the area under the standard normal curve to the right of z is equal to 1 .97.
00:17
So the z is equal to 1 .97 is given.
00:20
If i just graph the situation here, let's say this is the standard normal distribution.
00:26
And by the way, for the standard normal distribution, the mean value, which is denoted by, mu that would be 0 and the standard deviation which is denoted by sigma that would be 1.
00:37
So let's say this is the mean 0 and 1 .97 is over here so we need to get the right of this one means this shaded region we have to get the area of this shaded region so the probability of z is greater than 1 .97 in order to get this area we can use the normal cdf function of the tti calculator.
01:01
So what we have to do, we have to put the minimum value, the lower boundary for this shaded region, that is 1 .97.
01:08
When we look at the upper boundary, that goes to positive infinity, so i can put a very big number.
01:13
That means 10 to the upper 99...