Question

Find the Center and Radius of the circle by completing the square $x^2 + y^2 + 8x - 6y = 9$ Center $(4, 5)$; $r = 6$ Center $(4, -3)$; $r = 3$ Center $(5, -10)$; $r = 1$ Center $(-4, 3)$; $r = \sqrt{34} = 5.8$

          Find the Center and Radius of the circle by completing the square
$x^2 + y^2 + 8x - 6y = 9$
Center $(4, 5)$; $r = 6$
Center $(4, -3)$; $r = 3$
Center $(5, -10)$; $r = 1$
Center $(-4, 3)$; $r = \sqrt{34} = 5.8$

Find the Center and Radius of the circle by completing the square
x^2 + y^2 + 8x - 6y = 9
Center (4, 5); r = 6
Center (4, -3); r = 3
Center (5, -10); r = 1
Center (-4, 3); r = √(34) = 5.8

Added by Gabrielle V.

Geometry A Common Core Curriculum

Ron Larson, Laurie Boswell 1st Edition

Instant Answer

Solved by Expert Vysakh M

Step 1

The given equation is 22 + y^2 + 8y - 6y = 9. Combine like terms: y^2 + 2y + 22 = 9. Subtract 9 from both sides: y^2 + 2y + 13 = 0. Show more…

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Find the Center and Radius of the circle by completing the square 22 + y^2 + 8y - 6y = 9 Center (4, 5); r = 6 Center (4, 3); r = 3 Center (5,-10); r = 1 Center (4,3); r = âˆš34 - 5.8