Find the center of mass of a pentagon with five equal sides of length $a$, but with one triangle missing (Fig. 9.22 ). (Hint: See Example $9.3,$ and treat the pentagon as a group of triangles.) CAN'T COPY THE FIGURE
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Each triangle has a base of length 'a' and a height of 'h'. The height 'h' can be calculated using the Pythagorean theorem in a right triangle with sides 'a' and 'a/2'. So, h = sqrt(a^2 - (a/2)^2). The center of mass of each triangle is located at a distance of Show more…
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