Find the center of mass (xCM) of a thin rod of length 2 meters with a linear mass density that varies as \lambda (x) = x1/3, where “x” is the distance from the origin. The rod is located with its left end at x = 1 and its right end at x = 3.
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A long thin rod of length 2.0 m has a linear density λ(x) = Ax where x is the distance from the left end of the rod and A=3.0 kg/m. How far (in m) is the center of mass of the rod from the left end of the rod?
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If linear density of a rod of length $3 \mathrm{~m}$ varies as $\lambda=2+$ $x$, then the position of the centre of mass of the rod is (a) $\frac{7}{3} \mathrm{~m}$ (b) $\frac{12}{7} \mathrm{~m}$ (c) $\frac{10}{7} \mathrm{~m}$ (d) $\frac{9}{7} \mathrm{~m}$
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