Question

Find the component form of vector v given its magnitude is $||v||=9$ and the angle it makes with the positive x-axis is $\theta=60^\circ$. $\left\langle \frac{\sqrt{5}}{3}, \frac{9\sqrt{3}}{3} \right\rangle$ $\left\langle \frac{9\sqrt{3}}{4}, \frac{9\sqrt{3}}{4} \right\rangle$ $\left\langle \frac{9\sqrt{3}}{2}, \frac{9\sqrt{3}}{4} \right\rangle$ $\left\langle \frac{9}{2}, \frac{9\sqrt{5}}{2} \right\rangle$ $\left\langle \frac{9}{2}, \frac{9\sqrt{3}}{2} \right\rangle$

Name: find the component form of vector v given its magnitude is v9 and the angle it makes with the positive x axis is theta60circ leftlangle fracsqrt53 frac9sqrt33 rightrangle leftlangle frac9sqr 97093
Uploaded: 2021-07-16T02:11:53-08:00
Duration: 1 min 2 s
Channel: Tyler Moulton
Description: find the component form of vector v given its magnitude is v9 and the angle it makes with the positive x axis is theta60circ leftlangle fracsqrt53 frac9sqrt33 rightrangle leftlangle frac9sqr 97093

          Find the component form of vector v given its magnitude is $||v||=9$ and the angle it makes with the positive x-axis is $\theta=60^\circ$.
$\left\langle \frac{\sqrt{5}}{3}, \frac{9\sqrt{3}}{3} \right\rangle$
$\left\langle \frac{9\sqrt{3}}{4}, \frac{9\sqrt{3}}{4} \right\rangle$
$\left\langle \frac{9\sqrt{3}}{2}, \frac{9\sqrt{3}}{4} \right\rangle$
$\left\langle \frac{9}{2}, \frac{9\sqrt{5}}{2} \right\rangle$
$\left\langle \frac{9}{2}, \frac{9\sqrt{3}}{2} \right\rangle$

$find the component form of vector v given its magnitude is v9 and the angle it makes with the positive x axis is theta60circ leftlangle fracsqrt53 frac9sqrt33 rightrangle leftlangle frac9sqr 97093$

Added by Erik P.

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