Find the critical numbers or the function.

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Hi there. So for this problem we are asked to find the critical numbers of the function that is given and that function is G of ads is equal to that there root of 64- at the Square. So to find the critical points, what we need to do is to take the derivative of this function And set that equal to zero. So to obtain did you ever deaf? It's convenient to write this function as 64 minus X squared elevated to 1/3 because that is the same as as the theory route of this expression. So when we take the derivative of this, We obtain 1/3. This comes from this derivative of the external function. And these times we're going to obtain that that is 64 minus X squared elevated to to over three but it is negative. So it goes into the denominator. So we have this to over three. And internal derivative which is at the square minus at the square will give us Two times ads and we set this equal to zero. So the only way that this will give us zero is when ads is equal to zero. But another other critical points are where when and the denominator is zero and when the denominator is zero, we obtained from this two values, one of them is -8 and the order value adds is eight. So with this we conclude that the critical points or the or the critical numbers for these functions are minus eight, zero and eight. So there's a solution for this problem. Thank you

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