00:01
Hello students in this question we have given the properties of semi conductors at 300 kelvin that is effective density is equals to 1 ev that is number of neutrons is equal to 0 .19 and proton is equal to 0 .14 0 .10.
00:42
Er is equals to 12.
00:45
So we can say that the effective density, effective density is density of states of conduction band is equals to nc 2, 2 pi, m n star, kt divided by n squared, divided by power 3 by 2.
01:26
So by substituting values we got nc is equal to 2 .510, 2 .510 multiplied 10 to raise power 19, mn's star divided by among 3 by 2 centimeter cube.
01:51
Where we can say that mn's chart is equal to 0 .19.
02:00
So from this we got the mc is equal to 2 .150 multiplied 10 to 19, multiply 0 .19 divided by 3 by 2 .2.
02:12
So from here we got nc is equal to 0 .27 multiplied 10 to raise power 18 centimeter cube...