Find the distance between the plane $-4x + 8y - 2z = 12$ and the plane $2x - 4y + z = 2$.
Added by Angie P.
Close
Step 1
To find the normal vector of a plane, we can look at the coefficients of x, y, and z in the equation of the plane. The normal vector of the plane -4x+8y-2z=12 is (-4, 8, -2), and the normal vector of the plane 2x-4y+z=2 is (2, -4, 1). Show more…
Show all steps
Your feedback will help us improve your experience
Sri K and 89 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find the distance between the given parallel planes. 2x - 5y + z = 4, 4x - 10y + 2z = 2
Sri K.
Find the distance between the given parallel planes. 4x - 5y + z = 16, 8x - 10y + 2z = 2
Sarin S.
Find the distance between the given parallel planes. 2z = 6y - 4x, 3z = 2 - 6x + 9y
Adi S.
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD