Find the equation for the tangent line to the curve y = f(x) at the given x-value. f(x) = [(x - 2)^2 - x]^2 at x = 3
Added by Javier C.
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First, we need to find the derivative of the function f(x) at x=3. f'(x) = 2(x-2)(2x-1)(x^2-x+1) f'(3) = 2(1)(5)(7) = 70 Show more…
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