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In this problem, we are required to prove the three equations of motion which were given by newton, and they are v equal to u plus a .t .s.
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S equal to u .t plus half a t square, and the third equation is 2a .s.
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Equal to v.
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V.
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Square minus u square.
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So first we will prove this first equation of motion, and for that we simply use the knowledge that the acceleration is the rate of change of velocity.
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So let's rearrange.
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So we get dv as a times d t and let's integrate both sides within the limit.
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So when t is zero, initial velocity is u.
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When the time is t, the final velocity is v.
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So when we integrate and apply the limits, we get v minus u as a t.
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And rearranging this further, we get we as u plus a t...