Question

Find the exact values of the six trigonometric ratios of the angle \theta in the triangle. \sin(\theta) = \cos(\theta) = \tan(\theta) = \csc(\theta) = \sec(\theta) = \cot(\theta) = 200 205

          Find the exact values of the six trigonometric ratios of the angle \theta in the triangle.
\sin(\theta) = 
\cos(\theta) = 
\tan(\theta) = 
\csc(\theta) = 
\sec(\theta) = 
\cot(\theta) = 
200
205

Find the exact values of the six trigonometric ratios of the angle θin the triangle.
sin(θ) =
cos(θ) =
tan(θ) =
csc(θ) =
sec(θ) =
cot(θ) =
200
205

Added by Richard H.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Sai Sai

Step 1

Without any additional information, we cannot determine this. Assuming we are given the angle, let's call it angle A. sin(A) = opposite/hypotenuse = 200/205 = 0.9756 cos(A) = adjacent/hypotenuse = sqrt(205^2 - 200^2)/205 = 0.2191 tan(A) = opposite/adjacent = Show more…

Show all steps