Find the first three nonzero terms of the Taylor expansion for the given function and value of a. cos x $a = \frac{\pi}{3}$ ? $1 - \frac{1}{2!}(x - \frac{\pi}{3})^2 + \frac{1}{3!}(x - \frac{\pi}{3})^3 ...$ ? $\frac{1}{2}[1 - \sqrt{3}(x - \frac{\pi}{3}) - \frac{1}{2}(x - \frac{\pi}{3})^2 + ...$ ? $1 - \sqrt{3}(x - \frac{\pi}{3}) - \frac{1}{2}(x - \frac{\pi}{3})^2 + ...$ ? $(x - \frac{\pi}{3}) - \frac{1}{2!}(x - \frac{\pi}{3})^2 + \frac{1}{3!}(x - \frac{\pi}{3})^3 ...$
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7[(-3)^2+3[1-3]^3 = 01.7[9+3(-2)^3] = 01.7[9+3(-8)] = 01.7[9-24] = 01.7[-15] Show more…
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