Question

[2(cos 30° + i sin 30°)][5(cos 150° + i sin 150°)] =

Name: [2(cos 30° + i sin 30°)][5(cos 150° + i sin 150°)] =
Uploaded: 2022-01-07T16:42:49-08:00
Duration: 2 min 6 s
Channel: Shubham Sharma
Description: [2(cos 30° + i sin 30°)][5(cos 150° + i sin 150°)] =

          [2(cos 30° + i sin 30°)][5(cos 150° + i sin 150°)] =

Added by Richard J.

Introductory and Intermediate Algebra for College Students 4th

Robert Blitzer 4th Edition

Instant Answer

Solved by Expert Shubham Sharma

01/07/2022

Step 1

[2(cos30°+isin30°)] = 2(cos30°+isin30°) = 2(cos(30°) + i sin(30°)) = 2(√3/2 + i(1/2)) = √3 + i [5(cos150°+isin150°)] = 5(cos150°+isin150°) = 5(cos(150°) + i sin(150°)) = 5(-√3/2 + i(1/2)) = -5√3/2 + 5i/2 Show more…

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Find the following product, and write the product in rectangular form. [2(cos30+isin30][5cos150+isin150] [2(cos30+i sin 30][5(cos150+i sin 150]= Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.Type your answer in the form a + bi.