Find the following z values for the standard normal variable Z. Use Table 1. (Negative values should be indicated by a minus sign. Round your answers to 2 decimal places.) a. P(Z ≤ z) = 0.9186 b. P(Z > z) = 0.7254 c. P(-z ≤ Z ≤ z) = 0.72 d. P(0 ≤ Z ≤ z) = 0.4813
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Step 1
We want to find the z-value such that P(Z ≤ z) = 0.9186. Looking at the standard normal table, we find that the closest value to 0.9186 is at z = 1.34. So, the z-value for this case is: $$z = 1.34$$ b. We want to find the z-value such that P(Z > z) = 0.7254. Show more…
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