Given:
- Thermal conductivity of wood (K) = 0.12 W/m°C
- Area (A) = 1 m²
- Temperature of one surface (T1) = 50°C
- Temperature of the other surface (T2) = 30°C
- Thickness of the slab (L) = 1.8 cm = 0.018 m
Using the formula:
\[ H_A = -K \cdot A \cdot \frac{T2
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