Question

Find the interval [μ - zσ / √n, μ + zσ / √n] within which 90 percent of the sample means would be expected to fall, assuming that each sample is from a normal population. a. μ = 100, σ = 12, n = 36 b. μ = 2,000, σ = 150, n = 9 c. μ = 500, σ = 10, n = 25

Name: find the interval z n z n within which 90 percent of the sample means would be expected to fall assuming that each sample is from a normal populationa 100 12 n 36b 2000 150 n 9c 500 10 n 25 00686
Uploaded: 2023-07-27T21:49:47-08:00
Duration: 3 min 41 s
Channel: Ivan Kochetkov
Description: find the interval z n z n within which 90 percent of the sample means would be expected to fall assuming that each sample is from a normal populationa 100 12 n 36b 2000 150 n 9c 500 10 n 25 00686

          Find the interval [μ - zσ / √n, μ + zσ / √n] within which 90 percent of the sample means would be expected to fall, assuming that each sample is from a normal population.

a. μ = 100, σ = 12, n = 36
b. μ = 2,000, σ = 150, n = 9
c. μ = 500, σ = 10, n = 25

Added by Susan G.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Ivan Kochetkov

07/27/2023

Step 1

μ = 100, σ = 12, n = 36 First, we need to find the value of z for a 90% confidence level. Using a standard normal distribution table or calculator, we find that z = 1.645. Show more…

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Find the interval [μ - zσ / √n, μ + zσ / √n] within which 90 percent of the sample means would be expected to fall, assuming that each sample is from a normal population. a. μ = 100, σ = 12, n = 36 b. μ = 2,000, σ = 150, n = 9 c. μ = 500, σ = 10, n = 25