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Find the lengths of the missing sides if side a is opposite angle A, side b is opposite angle B, and side c is the hypotenuse.\\ $\cos(B) = \frac{4}{5}$, $a = 26$\ b = \\ c =

          Find the lengths of the missing sides if side a is opposite angle A, side b is opposite angle B, and side c is the hypotenuse.\\
$\cos(B) = \frac{4}{5}$, $a = 26$\
b = \\
c =
        
Find the lengths of the missing sides if side a is opposite angle A, side b is opposite angle B, and side c is the hypotenuse.

cos(B) = (4)/(5), a = 26b = 

c =

Added by Josefina M.

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Precalculus with Limits
Precalculus with Limits
Ron Larson 2nd Edition
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Find the lengths of the missing sides if side a is opposite angle A, side b is opposite angle B, and side c is the hypotenuse. cos(B)=(4)/(5),a=26 b= c= Find the lengths of the missing sides if side a is opposite angle A,side b is opposite angle B, and side c is the hypotenuse. a=26
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Transcript

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00:01 So in this problem, you're told that you have a right triangle.
00:03 So why don't we go ahead and draw that? so here's our right triangle.
00:06 And here's our right angle.
00:08 And we want to find the missing side lengths.
00:11 If a is opposite angle a, b is opposite angle b, and c is the hypotenuse.
00:15 So let's say that we have a, b, and c.
00:20 Or this really should be a capital c.
00:22 So c is our hypotenuse.
00:23 Side a is opposite angle a.
00:25 And side b is opposite angle b.
00:28 Now, we're told that the tangent of angle a is equal to 5 twelfths.
00:31 Remember, that's the ratio of the adjacent side, so that's here, divided by the opposite side, which would be down here.
00:38 But keep in mind that b is equal to 2, so we know what this length is.
00:44 So what we need to do is we need to make this into a proportion to figure out the side of length a.
00:49 So first off, we have the adjacent side over the opposite side is 5 twelfths, but we know that the adjacent side is actually equal to 2.
00:57 We can find a by setting up this proportion.
01:01 Proportion.
01:01 So to solve for a, let's cross multiply.
01:03 5 times a is 5a...
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