00:01
For delta x is equals to wx divided by 24ei into l cube minus 2l x square plus x cube.
00:13
It can be written as w divided by 24ei.
00:17
We can take inside so then we get l cube x minus 2l x cube plus x to the power 4 where all the parameter w, e, l, i are constant parameter.
00:37
Now to check whether x equals to l by 2 is a maximum parameter or not, we first find the critical points.
00:51
For that we find the del delta dash x which is the first derivative of delta with respect to x which is equals to d by dx of w divided by 24ei into l cube x minus 20 minus 2l x cube plus x4.
01:17
We can take constant outside so here we have w 24ei d by dx of l cube x minus 2l x cube plus x to the power 4.
01:34
After differentiating with respect to x we get w divided by 24ei into l cube minus when we differentiate with respect to x here we get 3x square and we multiply with 2 we get 6l x square plus 4 into x to the power 3.
01:53
So now this is the delta x.
01:55
Now to find critical points set delta dash x is equals to 0...
