Find the maximum torque, that can be safely Applied to a Shaft of 80mm diameter. The permissible angle of twist is 1.5 dagree in a length of 5m and Shear stress not to exceed 42MPa. TakeC = 84GPa
Added by Manisha M.
Step 1
The formula for J for a circular shaft is J = πd^4/32, where d is the diameter of the shaft. Substituting the given diameter into the formula, we get: J = π(0.08m)^4/32 = 3.18 x 10^-6 m^4 Show more…
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