Find the mean and standard deviation of the sampling distribution of sample means using the given information below: 1. μ = 35 and σ = 9; n = 64 2. μ = 28 and σ = 6; n = 81 3. μ = 52 and σ = 7; n = 100 4. μ = 582 and σ = 23.6; n = 1201
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**Case 1:** Given: μ = 35, σ = 9, n = 64 Sample mean (μ_x bar) = 35 Sample standard deviation (σ_x bar) = 9 / √64 = 9 / 8 = 1.125 **Case 2:** Given: μ = 28, σ = 6, n = 81 Sample mean (μ_x bar) = 28 Sample standard deviation (σ_x bar) = 6 / √81 = 6 / 9 = Show more…
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