Find the moment of inertia of a triangular section having a 50 mm base and a 60 mm height about an axis through its center of gravity and base. Answer: IG = 300 x 10^3 mm^4; IBase = 900 x 10^3 mm^4
Added by Timothy C.
Step 1
We are asked to find the moment of inertia of a triangular section with a base of 50 mm and a height of 60 mm. The moments of inertia required are about an axis through its center of gravity (IG) and about the base (IBase). Show more…
Show all steps
Close
Your feedback will help us improve your experience
Adi S and 82 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
find the moment of inertia of a rectangular section 60mm wide and 40mm deep about its center of gravity.
Adi S.
Determine the moment of inertia of the composite area about the Y-axis. The answer should look like this: I = Σ(Ai * di^2) S = 0 mm d1 = 50 mm d2 = 160 mm d3 = 40 mm J1 = 0 mm J2 = 0 mm
Sri K.
For a beam with the cross-section shown, find the area moment of inertia about the horizontal centroidal axis: 30 mm 150 mm 30 mm 100 mm 30 mm
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD