Question

Find the net force on $q_2$. $+8.0 \times 10^{-6} \text{ C}$ $+3.5 \times 10^{-6} \text{ C}$ $-2.5 \times 10^{-6} \text{ C}$ $q_1$ $q_2$ $q_3$ $0.10 \text{ m}$ $0.15 \text{ m}$ $\vec{F}_1 = \text{force exerted on } q_2 \text{ by } q_1$ $\vec{F}_3 = \text{force exerted on } q_2 \text{ by } q_3$ $\vec{F}_1 = [?] \text{ N}$ $\vec{F}_3 = \text{ } \text{ N}$ $\sum \vec{F} = \text{ } \text{ N}$ Remember: Forces pointing left are negative (-); forces pointing right are positive (+). newtons (N)

          Find the net force on $q_2$.

$+8.0 \times 10^{-6} \text{ C}$ 

$+3.5 \times 10^{-6} \text{ C}$

$-2.5 \times 10^{-6} \text{ C}$

$q_1$

$q_2$

$q_3$

$0.10 \text{ m}$

$0.15 \text{ m}$

$\vec{F}_1 = \text{force exerted on } q_2 \text{ by } q_1$

$\vec{F}_3 = \text{force exerted on } q_2 \text{ by } q_3$

$\vec{F}_1 = [?] \text{ N}$ 

$\vec{F}_3 = \text{ } \text{ N}$ 

$\sum \vec{F} = \text{ } \text{ N}$

Remember: Forces pointing left are negative (-);
forces pointing right are positive (+).
newtons (N)

Show more…

Find the net force on q2.

+8.0 × 10^-6 C

+3.5 × 10^-6 C

-2.5 × 10^-6 C

q1

q2

q3

0.10 m

0.15 m

F⃗1 = force exerted on q2 by q1

F⃗3 = force exerted on q2 by q3

F⃗1 = [?] N

F⃗3 = N

∑F⃗ = N

Remember: Forces pointing left are negative (-);
forces pointing right are positive (+).
newtons (N)

Added by Steven D.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

12/02/2023

Step 1

F₁ = k * q₁ * q₂ / r₁₂² where k = 9 x 10⁹ N m²/C² is Coulomb's constant, q₁ = 8.0 x 10⁻⁶ C, q₂ = 3.5 x 10⁻⁶ C, and r₁₂ = 0.10 m. F₁ = (9 x 10⁹ N m²/C²) * (8.0 x 10⁻⁶ C) * (3.5 x 10⁻⁶ C) / (0.10 m)² F₁ = 2.52 N Since q₁ and q₂ are both positive, the force is Show more…

Show all steps

lock

Thanks for your feedback!

Find the net force on q2. +8.0 x 10⁻⁶ C +q₁ 0.10 m +3.5 x 10⁻⁶ C +q₂ 0.15 m -2.5 x 10⁻⁶ C -q₃ F₁ = force exerted on q2 by q1 F₃ = force exerted on q2 by q3 F₁ = [?] N F₃ = N ΣF = N Remember: Forces pointing left are negative (-); forces pointing right are positive (+). newtons (N)

Play audio

Feedback

Powered by NumerAI

Adi S and 71 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Recommended Videos

Recommended Textbooks

Transcript

Ace is your personal tutor. It breaks down any question with clear steps so you can learn.

Start Using Ace

Continue solving this problem

Create a free account to:

View full step-by-step solution
Ask follow-up questions with Ace AI
Save progress and study later