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Hello students, in this question we have been given an nmr spectrum of this molecular formula.
00:06
Now we have to determine its entire structure.
00:08
So let's look at the peaks that are appearing.
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We can see that there is a huge peak of 9 hydrogen singlet.
00:16
So this comes for the tertiary butyl group like this.
00:21
So this must be a functional group or we can say substituent in our molecule.
00:25
Now 4 hydrogens are giving a peak higher than 2.
00:30
So this appears when we have ch2 groups adjacent to the carbonyl group.
00:37
So this oxygen must be part of a ketone on which these two ch2 groups must be identical.
00:44
Now we can see that there are 4 hydrogen atoms giving a peak here.
00:50
So one carbon atom here cannot be connected to all 4 hydrogens.
00:54
So this will also be a part of two identical ch2 groups...