00:01
Solving party of this problem, so here i will use the formula nge is equal to n -a row ge by a -g -e.
00:12
So putting the value in this equation 6 .022, multiplication 10 to the power 23, multiplication 5 .32 by 72 .59, multiplication 10 to the power 6, which is equal to 4 .41.
00:31
Multiplication 10 to the power 28 atoms per m to the power minus 3.
00:42
Going forward and calculating the value of n s i that is number of silicon atom per cubic meter which is equal to n a row s i by a as i which is equal to 6 .022 multiplication 10 to the power 23 multiplication 2 .33 by 28 .09 multiplication 10 to the power 6 which is equal to 4 .995 multiplication 10 to the power 28 atoms per m to the power minus 3 now electron free per atom let it be e .p is equal to nge by capital nge, which is equal to 1 multiplication 10 to the power 19 by 4 .41, multiplication 10 to the power 28, which is equal to 2 .268 multiplication 10 to the power minus 10.
01:50
Now, electron free per atom 2 is equal to n -si by capital n -si, which is equal to 1 multiplication 10 to the power 16 by 4 .995 multiplication 10 to the power 28, which is equal to 2 .002 multiplication 10 to the power minus 13.
02:19
Now solving part b...