4.19 ?? ??? ?? ?????? ?? ???? $\frac{C(s)}{R(s)}$? ????. ?? P4.19 $H_3(s)$ $+$ $+$ $+$ $R$ $G_1(s)$ $G_2(s)$ $C$ $+$ $H_1(s)$ $H_2(s)$ $G_3(s)$
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The forward path from \( R(s) \) to \( C(s) \) is through \( G_1(s) \) and \( G_2(s) \). Therefore, the forward path transfer function is: \[ G(s) = G_1(s) \cdot G_2(s) \] Show more…
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