00:01
For this problem, you have to consider some key information.
00:04
So if we first know that we start at the point zero minus 6 .5, then that means that we're starting down here.
00:13
And so secondly, we know that the x position starts with a value of zero, and the y position starts with a value of that's proportional to 1.
00:24
And so therefore, the y of t should be proportional to cosine, and x should be proportional to sign in time.
00:35
And so secondly, we would like to find the angular frequency to put into this trigonometric function.
00:42
And so we know that the period is equal to 2 pi over the angular frequency.
00:51
And so, therefore, the angular frequency is just equal to 2 pi over the period.
00:58
And since the period is equal to 2 pi in the question, you get that the frequency is just a 1.
01:05
And so inside here we can just put t...