00:01
Hello everyone, let's solve the given question.
00:02
So, as according to the question in part, first x square plus y square plus z square minus 2 is equals to 0.
00:12
On the partially differentiate, we get 2x plus 0 plus 2z minus 1 del z over del x is equals to 0.
00:29
Then we get del z over del x is equals to minus 2x divided 2z minus 1.
00:35
Now, moving to part second of this question and we are having u z is equals to u cube plus v cube minus 3uv and u is equals to x plus y, v is equals to x minus y.
00:49
So, as to be moving further, the del z over del x is equals to del z over del u, del u over del x plus del z over del v, del v over del x.
01:04
So, it is equals to del z over del u will be 3u square minus 3v and plus del the 3v square minus 3u...