00:01
So, in this question, for the a part, b value is given that is 10 sine omega t plus 30 and for the i part, it is also given that is 5 sine omega t plus 70.
00:19
So, basically for the phase difference, it will be calculated as 70 minus 30 that is equal to 40 degree.
00:27
So, we can say as i leads to, i leads to b by 40 degree or vice versa.
00:39
Vice versa means i leads to, v leads to i by 40 degree.
00:44
So, let us plot a graph.
00:46
So, basically here we have the graph which is 0 and this is x axis will be of omega t.
00:53
So, this is pi by 2, this is pi and this is 3 pi by 2.
00:59
Now, in the left hand side of the x axis or we can say as in the left hand side of omega t, it is minus 80 degree, it is minus 70 degree and in the y axis, we have 5, we have 10.
01:13
So, basically this one graph is going from this 5, touching 5 and moving to this, it is going like and the another graph is starting from minus 70 degree, touching 5, moving in between of pi by 2 and pi and touching to 3 pi by 2.
01:42
This is basically of v graph and this is of i1.
01:49
This is the required answer for the a part.
01:51
Now, for the b part, we have and this v is equal to 10 sin omega t minus 20 and i is equal to 15 sin omega t plus 60...