Question

Find the point of intersection of the lines $L_1: x = \frac{y-2}{-1} = z - 1 = t$, $L_2: \frac{x-2}{2} = y - 3 = \frac{z-6}{5} = s$, and then find the plane determined by these lines.

          Find the point of intersection of the lines
$L_1: x = \frac{y-2}{-1} = z - 1 = t$, $L_2: \frac{x-2}{2} = y - 3 = \frac{z-6}{5} = s$,
and then find the plane determined by these lines.

Find the point of intersection of the lines
L1: x = (y-2)/(-1) = z - 1 = t, L2: (x-2)/(2) = y - 3 = (z-6)/(5) = s,
and then find the plane determined by these lines.

Added by Rachael W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Vivek K

Step 1

For L1: x = y - 2 For L2: x - 2 = z - 1 = t Since we are given that x = -1 and y = 2, we can substitute these values into the equation for L1 to find the value of z and t. -1 = 2 - 2 -1 = 0 Since -1 does not equal 0, there is no solution for the system of Show more…

Show all steps