00:01
Okay, i want to find a polynomial of degree three that matches this graph.
00:05
Okay, and to do that, i'm going to grab the zeros.
00:09
I have a zero at three, and i have a zero at five.
00:14
So that means i'm going to have factors x minus three and x minus five.
00:23
But is that enough? the answer is no, because right now what i'm looking at is a second degree polynomial, and i want a third degree, but that's okay, because at my 0 positive 3, you can see that the graph comes up, touches the x -axis, and comes back down.
00:41
It doesn't cross.
00:43
So what that means is this 3 -0 has to have a multiplicity that's an even number.
00:50
So i'm going to make this 0 a multiplicity of 2...