Find the power (in W) dissipated in each of these extension cords. (a) an extension cord having a 0.0660 ? resistance and through which 4.15 A is flowing W (b) a cheaper cord utilizing thinner wire and with a resistance of 0.330 ? and through which 4.15 A is flowing W
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066 Ī© and a current of 4 A flowing through it. Given: Resistance (R) = 0.066 Ī© Current (I) = 4 A Using the formula P = I^2 * R, where P is power: P = (4 A)^2 * 0.066 Ī© P = 16 A^2 * 0.066 Ī© P = 1.056 W Show moreā¦
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