00:01
Okay, so for this problem, it states a basketball player hits her shot 42 % of the time.
00:06
So hits out of the total percentage.
00:12
So that's 42 out of 100, which means no hits would be 58 out of the total.
00:25
Okay? and if she takes four shots during the game, what is the probability that she misses the first shot? and hits the last three shots.
00:36
So that would be 58 out of 100, okay? then it would be 42 out of 99, and then times 41 out of 98 times 40 out of 97.
00:59
So then what i would have to do is, i would have to multiply all three of these.
01:10
So i'm going to do some simplification.
01:13
So i would do 58 divided by 2 is 29 out of 50.
01:26
Oh, times 42 divided by 3 is 14 out of 33 times.
01:34
And then i can cross simplify here...