00:01
For this question, there's given the problem here.
00:05
So the mean value for this distribution is equal to the p had that was given as 63%, which is 0 .63.
00:13
So we can just say the mean value here, which is 0 .63.
00:17
And so the number of people here, this is 250.
00:21
This is sample size.
00:22
So what we need? we need the mean.
00:24
Actually, we need that.
00:25
So we got the mean before in the standard division.
00:28
So the standard division has the formula which is the square of this is p times 1 minus p and divided by n so let's say the standard division denoted by sigma here this is squared of 0 .63 times 1 minus 0 .63 which is 0 .37 right and then divide this number by the number of item here which is 250 let's get the answer this is second and the squared sign so we have 0 .63 times this is 0 .37 and divided by this is 250.
01:01
So the answer would be, which is, this is 0 .03.
01:06
So the answer here, this is 0 .0 .03 and 05.
01:11
This is the standard division we have here.
01:13
So we can define the random variable x.
01:15
This is normally distributed.
01:18
So the mean value is 0 .63 and the standard division is 0 .305.
01:24
So for this part of the question, what we have to do, we have to fight that the 59 % less than is unusual or not, so we have to get the probability here, the random variable x, which is less than, 59 % is 0 .59...