00:01
Okay, so in this long division problem, my divisor is x minus 3, and my dividend under this root is x to the third minus 12x plus 10.
00:10
Now, under my dividend, i have to have decreasing exponents.
00:14
So i have x to the third.
00:15
I don't have an x squared.
00:17
Okay, that's important to know.
00:18
I have x to the first and then a constant.
00:21
Since i don't have an x squared, i'm going to add 0x squared.
00:24
So that needs to be under the dividend.
00:27
My divisor is just x to the first and the constant.
00:29
Said so i'm fine.
00:30
So in order to do long division i'm thinking what do i have to multiply x by to get x to the third? well i need two more x's.
00:38
X squared bring x squared down multiply x squared to both x which is x to the third and negative three which is negative three x squared.
00:49
Then i'm subtracting to cancel.
00:52
So i'm subtracting so i'm going to change the signs here distribute the a negative.
00:56
1x to the third minus x to the third cancels.
00:59
And 0 plus 3x squared is just 3x squared.
01:02
Bring down my next term.
01:05
My new first term that i'm comparing is x and 3x squared...