Question

Find the quotient $\frac{z_1}{z_2}$ of the complex numbers. Leave your answer in polar form. $z_1 = 5(\cos \frac{\pi}{4} + i \sin \frac{\pi}{4})$ $z_2 = 7(\cos \frac{\pi}{9} + i \sin \frac{\pi}{9})$ $\frac{z_1}{z_2} = $

Name: find the quotient fracz1z2 of the complex numbers leave your answer in polar form z1 5cos fracpi4 i sin fracpi4 z2 7cos fracpi9 i sin fracpi9 fracz1z2 98121
Uploaded: 2020-04-10T18:29:48-08:00
Duration: 1 min 22 s
Channel: Tom Greenwood
Description: find the quotient fracz1z2 of the complex numbers leave your answer in polar form z1 5cos fracpi4 i sin fracpi4 z2 7cos fracpi9 i sin fracpi9 fracz1z2 98121

          Find the quotient $\frac{z_1}{z_2}$ of the complex numbers. Leave your answer in polar form.
$z_1 = 5(\cos \frac{\pi}{4} + i \sin \frac{\pi}{4})$
$z_2 = 7(\cos \frac{\pi}{9} + i \sin \frac{\pi}{9})$
$\frac{z_1}{z_2} = $

$find the quotient fracz1z2 of the complex numbers leave your answer in polar form z1 5cos fracpi4 i sin fracpi4 z2 7cos fracpi9 i sin fracpi9 fracz1z2 98121$

Added by Concepci-N Y.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Tom Greenwood

04/10/2020

Step 1

$$ \frac{z_1}{z_2} = \frac{5}{7} \left( \cos \left( \frac{\pi}{4} - \frac{\pi}{9} \right) + i \sin \left( \frac{\pi}{4} - \frac{\pi}{9} \right) \right) $$ Show more…

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Find the quotient $\frac{z_1}{z_2}$ of the complex numbers. Leave your answer in polar form. $z_1 = 5(\cos \frac{\pi}{4} + i \sin \frac{\pi}{4})$ $z_2 = 7(\cos \frac{\pi}{9} + i \sin \frac{\pi}{9})$ $\frac{z_1}{z_2} = $