00:01
When a charged particle enters a region of magnetic field, it follows a circular path with radius called radius of curvature that is solved as m v over qb, where r is the radius of curvature in meters, m is the mass of the charged particle in kilograms, v is its speed in meters per second, q is its charge in columns, and b is the magnetic field strength.
00:23
In this problem, we're given with a proton that possesses kinetic energy of 0 .220 mega electrode volts.
00:33
When it enters a region of electric field, that is magnetic field rather, which magnetic field strength is 1 .30 tesla.
00:48
Since this is a proton, then we can identify the mass and the charges as follows.
00:54
So we want to find the ratios of curvature.
00:57
We will start by first solving for the speed.
01:00
Given with the kinetic energy, we can solve for the speed as follows.
01:06
So first, the formula, recall that the formula for kinetic energy is 1 half mv squared...