00:01
All right, so in this problem we've been given the difference and the intersection of two sets and been asked to find what those two sets are.
00:09
So let's first take a look.
00:10
We know that we're looking for set a and we know that we're looking for set b.
00:16
And we know that a intersect b is 3, 6, and 9.
00:21
So we know that a and b both contain 3, 6, and 9.
00:29
Then what we know here is that if we take a and remove b, this is what's going to be left.
00:38
So this is the result of a take away what they have in common.
00:43
So this is going to be what is in a.
00:47
And the same over here.
00:49
We're starting with b and we take away a.
00:51
So if we start with b and take away these things that they have in common, 2 and 10 we are getting left over.
01:00
So here are a and b.
01:03
And now we're asked to show that a minus b minus c is a subset of a c.
01:11
So let's start.
01:13
We know that a minus b minus c is going to be all of the x values where x is an element of a, but x is not an element of b.
01:28
And x can't be an element of c.
01:32
So that's how that translates.
01:34
But we also know that this is commutative.
01:37
We know that it doesn't matter what order we do these ands in.
01:42
So this says that x is an element of a and x is not an element of c.
01:48
It is both commutative and associative, and then x is not an element of b.
01:53
Well, what this says is that a minus c, minus b, and that would obviously be a subset of a minus c, because if we start with ac and we take some things out of there, that's still going to be a subset of b.
02:10
So what this is saying is if x is an element of a minus b, minus c, it is an element of a, and not an element of b of b.
02:37
Or c.
02:40
So we know then if x is an element of a minus b minus c then it's still going to be an element in a minus c and that's what we're trying to show.
03:11
And then we're asked to draw some venn diagrams.
03:15
And what i've done here is i've gone ahead and drawn some example venn diagrams of what these things look like...