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Find the solutions to the equation in the interval $0 \le \theta \le \frac{\pi}{2}$. Enter your answers as a comma-separated list. $2\cos(4\theta) - 1 = 0$ $\theta = $ 

          Find the solutions to the equation in the interval $0 \le \theta \le \frac{\pi}{2}$. Enter your answers as a comma-separated list.
$2\cos(4\theta) - 1 = 0$
$\theta = $
Find the solutions to the equation in the interval 0 ≤θ≤(π)/(2). Enter your answers as a comma-separated list. 2cos(4θ) - 1 = 0 θ =

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Precalculus with Limits
Precalculus with Limits
Ron Larson 2nd Edition
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Find the solutions to the equation in the interval 0 <= θ <= π/2. Enter your answers as a comma-separated list. 2cos(4θ) - 1 = 0 θ = Find the solutions to the equation in the interval 0 <= θ <= π/2. Enter your answers as a comma-separated list. 2cos(40) = 10
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00:01 Here in this problem we have given cosine 2 theta minus tangent theta is equal to 1 and we are asked to find the solution of equation that lies in the interval 0 .2 pi so here we have cosine 2 theta minus tangent theta is equal to 1 now adding tangent theta on both side we get cosine 2 theta is equal to 1 plus tangent theta since we know that cosine 2 theta 2x2 theta is 2 into cosine square theta minus 1 it would be equals to 1 plus tangent theta now by using the trigonometric formula we get 2 into cosine square theta would be 2 upon 1 plus tangent square theta minus 1 is equals to 1 plus tangent theta by simplifying it we get 1 minus tangent square theta upon 1 plus tangent square theta minus 1 plus tangent theta is equal to 0.
01:38 Now by putting each factor is equal to 0 we get 1 plus tangent theta is equal to 0 or 1 minus tangent theta upon 1 plus tangent square theta minus 1 is equal to 0.
01:59 From here we get tangent theta is equal to minus 1 or here we get tangent square theta plus tangent theta is equal to 0...
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