00:01
For this question, we need to find the standard form of the equation of the ellipse with the characteristics, or rather that contain the points 0, negative 3, 2, negative 2, 4, negative 3, and 2, negative 4.
00:16
So essentially here we're given four points.
00:19
So the best place to start is by plotting those on the graph.
00:23
You can see we have points at both 0, negative 3 and also at 4, negative 3.
00:30
They also have points at 2, negative 2 and 2, negative 4.
00:36
So we can see the ellipse here.
00:38
We can see that we actually were given the vertices and the co -vertices.
00:44
So the vertices are the ones that are along the major axis.
00:48
And the major axis is the line going through the ellipse long ways.
00:53
So given this, we can go ahead and identify the vertices as being points 0, negative 3, and also 4, negative 3.
01:10
And the co -vertices are located at 2, negative 2, and also 2, negative 4.
01:20
We need to understand the formula for the standard form of an equation of an ellipse.
01:26
In this case, the major axis is horizontal, which means i use the formula x minus h squared divided by a squared plus y minus k squared divided by b squared equals 1.
01:44
Where h comma k is equal to the center, and the major axis has a length equal to 2a.
01:56
Let's start by considering the information we have...