"Find the temperature difference between two sides of a steel plate 4 cm thick, when heat is transmitted through the plate at the rate of 400 k cal per minute per square metre at steady state. Thermal conductivity of steel is 0.026 kcal/m s K"
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"The temperature difference between two sides of an iron plate, 4 cm thick, is 10 °C. Heat is transmitted through the plate at the rate of 800 kcal per minute per square metre at steady state. Find the thermal conductivity of iron."
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A metal plate 4.00 mm thick has a temperature difference of 32.0 °C between its faces. It transmits 200 kcal/h through an area of 5.00 cm^2. Calculate the thermal conductivity of this metal in W/m·K.
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A metal plate $4.00 \mathrm{~mm}$ thick has a temperature difference of $32.0^{\circ} \mathrm{C}$ between its faces. It transmits $200 \mathrm{kcal} / \mathrm{h}$ through an area of $5.00$ $\mathrm{cm}^{2}$. Calculate the thermal conductivity of this metal in $\mathrm{W} / \mathrm{m} \cdot \mathrm{K}$. $$ \begin{aligned} k_{T} &=\frac{\Delta Q}{\Delta t} \frac{L}{A\left(T_{1}-T_{2}\right)}=\frac{\left(2.00 \times 10^{5} \mathrm{cal}\right)(4.184 \mathrm{~J} / \mathrm{cal})}{(1.00 \mathrm{~h})(3600 \mathrm{~s} / \mathrm{h})} \frac{4.00 \times 10^{-3} \mathrm{~m}}{\left(5.00 \times 10^{-4} \mathrm{~m}^{2}\right)(32.0 \mathrm{~K})} \\ &=58.5 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K} \end{aligned} $$
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