Find the topology of the network if the following table is the routing table four router R1. Mask Network address Next-hop address Interface /26 202.14.17.192 --- m2 /24 130.254.12.0 --- m0 /22 187.31.200.0 49.151.225.1 m1 /19 49.151.224.0 --- m1 default default 130.254.12.51 m0
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- /26 202.14.17.192 -> m2 - /24 130.254.12.0 -> mo - /22 187.31.200.0 -> m1 - /19 49.151.224.0 -> m1 Show more…
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Suppose a router has built up the routing table shown in the table below. The router can deliver packets directly over interfaces 0 and 1, or it can forward packets to routers R2, R3, or R4. Assume that the router does the longest prefix match. Describe what the router does with a packet addressed to each of the following destinations: a. 128.96.171.92 b. 128.96.167.151 c. 128.96.163.151 d. 128.96.169.192 e. 128.96.165.121
Aarya B.
192.168.1.97/27 192.168.1.98/27 R1 192.168.1.55/27 192.168.1.69/28 192.168.1.129/27 R2 192.168.1.222/28 Host 1 Host 2 Host 3 Host 4 IP: 192.168.1.35 IP: 192.168.1.72 SM: 255.255.255.224 SM: 255.255.255.240 GW: 192.168.1.55 GW: 192.168.1.69 IP: 192.168.1.130 IP: 192.168.1.225 SM: 255.255.255.224 SM: 255.255.255.240 GW: 192.168.1.129 GW: 192.168.1.222 In the network diagram above, determine why Host 4 cannot ping Host 1. Explain what happens to the ICMP packets. The IP addresses given above are interface addresses for the routers (with the corresponding mask length given in CIDR notation). They are not subnet addresses. You can reasonably assume that the routers R1 and R2 have advertised the network routes they know about to each other, and each router has learned about network routes by way of the direct connections to their respective networks. Such routes are installed in the routing table for the router and will be advertised to its neighbors.
Akash M.
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