00:01
Hello students, in this question we have to find the transfer function.
00:06
So for loop 1 taking this i1 and this will be the loop for i2 and for next b circuit taking this is the loop for current i1 and this is the loop for current i2.
00:28
Now let's start to solve.
00:32
First write the mesh equation for loop 1.
00:36
We have i1 plus di1 minus i2 divided by dt is equal to v.
00:50
Now applying laplace transform we get i1 s plus si1 s minus i2 s is equal to vt.
01:08
Now this can be written as i1 s will be equal to v s plus si2 s divided by 1 plus s.
01:21
Now taking this equation 1.
01:23
Now let's write the mesh equation for loop 2.
01:27
This is for loop 1 and this is for loop 2.
01:29
So this will be i2 t plus di2 t minus i1 t divided by dt is equal to 0.
01:44
Now applying laplace transform we get i2 s plus si2 s minus s i1 s is equal to 0.
01:57
So after solving and substituting for i1 we have minus s sv plus si2 s divided by 1 plus s plus 1 plus s i2 s is equal to 0.
02:19
After further solving we get i2 will be equal to sv1 s divided by 2s plus 1.
02:29
Taking this equation 2, the output voltage is v0 will be equal to i2 t.
02:36
Now applying laplace transform we get v0 s is equal to i2 s...