Find the value of $k$ for which $det \begin{bmatrix} 2 & 1 \ -1 & k \end{bmatrix} = det \begin{bmatrix} 3 & 1 \ -3 & -1 \end{bmatrix}$
Added by Jennifer P.
Close
Step 1
So, det([[2,1],[-1,k]]) = (2*k) - (-1*1) = 2k + 1. Show more…
Show all steps
Your feedback will help us improve your experience
Anas Venkitta and 61 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The values of $\mathrm{K}$ ' such that the roots of the equation $3 \mathrm{x}^{2}+\left(\mathrm{k}^{2}-\mathrm{k}-2\right) \mathrm{x}-17=0$ are equal and opposite in sign are (a) $\{-1,2\}$ (b) $\{1,2\}$ (c) $\{1,-2\}$ (d) $\{-1,-2\}$
Using Solution Points For what values of $k$ does the graph of $y^{2}=4 k x$ pass through the point? $$\begin{array}{ll}{\text { (a) }(1,1)} & {\text { (b) }(2,4)} \\ {\text { (c) }(0,0)} & {\text { (d) }(3,3)}\end{array}$$
Preparation for Calculus
Graphs and Models
Madhur L.
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD