Find the wavelength of the radiation emitted when a hydrogen atom makes a transition from the $n=6$ to the $n=3$ state. ( W tutorial: hydrogen atom)
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The formula is given by: \[\frac{1}{\lambda} = R_H \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right)\] where: \(\lambda\) = wavelength of the radiation emitted \(R_H\) = Rydberg constant for hydrogen (\(1.097 \times 10^7 m^{-1}\)) \(n_1\) = initial energy Show more…
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