Question

Find the work done by the vector field \((2x + yz, x^2 + 6)\) on a particle moving along the boundary of the rectangle \(0 \le x \le 6, 0 \le y \le 5\) in the counterclockwise direction. (The force is measured in newtons, length in meters, work in joules =(newton-meters).) W = 90 joules

          Find the work done by the vector field \((2x + yz, x^2 + 6)\) on a particle moving along the boundary of the rectangle \(0 \le x \le 6, 0 \le y \le 5\) in the counterclockwise direction.
(The force is measured in newtons, length in meters, work in joules =(newton-meters).)
W = 90 joules

Find the work done by the vector field (2x + yz, x^2 + 6) on a particle moving along the boundary of the rectangle 0 ≤ x ≤ 6, 0 ≤ y ≤ 5 in the counterclockwise direction.
(The force is measured in newtons, length in meters, work in joules =(newton-meters).)
W = 90 joules

Added by Brian A.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

07/02/2023

Step 1

We can do this by breaking the boundary into four line segments and then parameterizing each segment. Step 2: The boundary consists of the following line segments: Show more…

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Find the work done by the vector field (2x + yx, x²+6) on a particle moving along the boundary of the rectangle 0 ≤ x ≤ 6,0 ≤ y ≤ 5 in the counterclockwise direction. (The force is measured in newtons, length in meters, work in joules=(newton-meters).) W = 90 joules Find the work done by the vector field2+yz+6on a particle moving along the boundary of the rectangle 060y5 in the counterclockwise direction (The force is measured in newtons,length in meters,work in joules=(newton-meters)) W=90joules