Question

1. Find the $x$-intercept of the line $-2x + 5y = 7$ $(x, y) = (0, -\frac{7}{2})$ $(x, y) = (0, \frac{7}{5})$ $(x, y) = (\frac{7}{5}, 0)$ $(x, y) = (-\frac{7}{2}, 0)$ $(x, y) = (\frac{2}{5}, 0)$

          1. Find the $x$-intercept of the line $-2x + 5y = 7$
$(x, y) = (0, -\frac{7}{2})$
$(x, y) = (0, \frac{7}{5})$
$(x, y) = (\frac{7}{5}, 0)$
$(x, y) = (-\frac{7}{2}, 0)$
$(x, y) = (\frac{2}{5}, 0)$

1. Find the x-intercept of the line -2x + 5y = 7
(x, y) = (0, -(7)/(2))
(x, y) = (0, (7)/(5))
(x, y) = ((7)/(5), 0)
(x, y) = (-(7)/(2), 0)
(x, y) = ((2)/(5), 0)

Added by Nicole M.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Heather Zimmers

04/22/2020

Step 1

Step 1: Identify the given equation The given equation is -2x + 5y = 7. Show more…

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Find the x-intercept of the line -2x+5y=7 (x,y)=(0,-(7)/(2)) (x,y)=(0,(7)/(5)) (x,y)=((7)/(5),0) (x,y)=(-(7)/(2),0) (x,y)=((2)/(5),0) 1.Find the -intercept of the line -2 + 5y= 7 (x,y= O (,y)= (0, 3) O (r.u)=(.0) O (,v)=(-.0) O (,y)=(3,0)